Electronic Engineer Discuss

View: 7814|Reply: 6
Print Prev. thread Next thread

Hantek DSO5202BM: bug when drawing waveform dots

[Copy link]

24

Threads

119

Posts

119

Credits

注册会员

Rank: 2

Credits
119
Jump to specified page
1#
Post time 2016-7-20 03:16:36 | Show all posts Reply Awards |Descending |Read mode
Edited by Oleg10011001 at 2016-7-20 03:18

In the menu "Display", you can choose how to draw a waveform: vectors or dots. If you select a drawing mode waveform by using dots and then put the scan time, for example, to 2ns, then, when the oscilloscope in single-window mode, you can see that the waveform is drawn with vectors at the dots of need, for example:



At the same time, when operating in the mode of the oscilloscope with two windows, a window is drawn lower waveform is true - dots, for example:




P.S: Sorry my bad english.



Reply

Use magic Report

24

Threads

119

Posts

119

Credits

注册会员

Rank: 2

Credits
119
2#
 Author| Post time 2016-7-21 16:45:43 | Show all posts
Edited by Oleg10011001 at 2016-7-22 00:23

I'm sorry, I do not quite understand how it is possible that in this case it is not clear what the dots (mean of 800 and 4000) ... As you can see, in both cases prescribed scan time - 2ns. At this sampling frequency of the signal - 1Gs/sec. Thus, it appears that we must have only two dots on the cell. The number of cells we have, on the width of the screen, not much different. In one mode, the window 19 cells, and in the lower window when two windows 16 cells. Thus, one can easily calculate that the width of the screen we can have only 38 dots and 32 dots, respectively; their density does not differ significantly. More dots can only be used in an equivalent sample 25Gs/sec, but it is not used here. What is it I do not mean right?



24

Threads

119

Posts

119

Credits

注册会员

Rank: 2

Credits
119
3#
 Author| Post time 2016-7-22 00:18:07 | Show all posts
Edited by Oleg10011001 at 2016-7-22 03:41

In other words, when the scan time is set to 2ns on the screen we see a part of the signal duration of a maximum of 38ns. During the specified time (38ns) oscilloscope digitizes the signal at a rate 1Gs / sec will have time to make only 38 samples and accordingly the waveform portion is placed on the screen shall consist of a maximum of 38 dots (of which come from the mentioned 800 dots you or the more than 4000 dots I do not understand). I think that 4000 dots refer to everything written in the memory of the signal, because 4K memory used. However, in this case, the record 4000 dots takes a lot of screens with built-in scan time 2ns. On one screen, fit only a maximum of 38 dots, and they can draw dots, rather than vectors. What I did not understand correctly?















24

Threads

119

Posts

119

Credits

注册会员

Rank: 2

Credits
119
4#
 Author| Post time 2016-7-22 19:05:48 | Show all posts
Thank you for the explanation! It turns out I did not understand the true purpose of the dots on the waveform.

You have to log in before you can reply Login | Register

Points Rules

Dark room|Mobile|Archiver|Electronic Engineer Discuss

2024-5-16 04:35 GMT+8 , Processed in 0.170092 second(s), 21 queries .

Powered by Discuz! X3.2

© 2001-2013 Comsenz Inc.

Quick Reply To Top Return to the list