Title: Hantek DSO5202BM: bug when drawing waveform dots [Print this page] Author: Oleg10011001 Time: 2016-7-20 03:16 Title: Hantek DSO5202BM: bug when drawing waveform dots Edited by Oleg10011001 at 2016-7-20 03:18
In the menu "Display", you can choose how to draw a waveform: vectors or dots. If you select a drawing mode waveform by using dots and then put the scan time, for example, to 2ns, then, when the oscilloscope in single-window mode, you can see that the waveform is drawn with vectors at the dots of need, for example:
At the same time, when operating in the mode of the oscilloscope with two windows, a window is drawn lower waveform is true - dots, for example:
P.S: Sorry my bad english.
Author: amy Time: 2016-7-21 16:03
Dir sir,
In the second picture, the display dots is 4000, but the minor window displays the points that the data from major window be magnified 100 times. So you can see the points.
In the first picture, the display dots is 800, thay are very dense. So you can't see the points. Author: Oleg10011001 Time: 2016-7-21 16:45 Edited by Oleg10011001 at 2016-7-22 00:23
I'm sorry, I do not quite understand how it is possible that in this case it is not clear what the dots (mean of 800 and 4000) ... As you can see, in both cases prescribed scan time - 2ns. At this sampling frequency of the signal - 1Gs/sec. Thus, it appears that we must have only two dots on the cell. The number of cells we have, on the width of the screen, not much different. In one mode, the window 19 cells, and in the lower window when two windows 16 cells. Thus, one can easily calculate that the width of the screen we can have only 38 dots and 32 dots, respectively; their density does not differ significantly. More dots can only be used in an equivalent sample 25Gs/sec, but it is not used here. What is it I do not mean right?
Author: Oleg10011001 Time: 2016-7-22 00:18 Edited by Oleg10011001 at 2016-7-22 03:41
In other words, when the scan time is set to 2ns on the screen we see a part of the signal duration of a maximum of 38ns. During the specified time (38ns) oscilloscope digitizes the signal at a rate 1Gs / sec will have time to make only 38 samples and accordingly the waveform portion is placed on the screen shall consist of a maximum of 38 dots (of which come from the mentioned 800 dots you or the more than 4000 dots I do not understand). I think that 4000 dots refer to everything written in the memory of the signal, because 4K memory used. However, in this case, the record 4000 dots takes a lot of screens with built-in scan time 2ns. On one screen, fit only a maximum of 38 dots, and they can draw dots, rather than vectors. What I did not understand correctly?
Author: amy Time: 2016-7-22 13:25 Edited by amy at 2016-7-22 13:28
Instructions:
Display dots: Please click “Utility->System status” to check the display dots;
The quantity of the display screen grids is 20(permanent).
In your first picture, the display dots are 800, there are 20 grids. So there are 40 dots in every grid.
[attach]1037[/attach]
You can set the Volt/Div to 50mV to see the dots clearly.
[attach]1038[/attach]
[attach]1039[/attach]
[attach]1042[/attach]
In double window mode, in the major window, the display dots are 3200. There are 20 grids. There are 160 dots in every grid of the major window.
The minor window displays the dots that the data from major window be magnified 100 times.
So there are about 1.6 dots in every grid of the minor window.
[attach]1041[/attach]
Author: Oleg10011001 Time: 2016-7-22 19:05
Thank you for the explanation! It turns out I did not understand the true purpose of the dots on the waveform.
Author: amy Time: 2016-7-23 15:45
The dots and vectors are waveform display forms just.
The dots type displays the sampling dots.
The vectors type draws waveform via connecting two dots.
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It turns out I did not understand the true purpose of the dots on the waveform.